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6x^2+7=79
We move all terms to the left:
6x^2+7-(79)=0
We add all the numbers together, and all the variables
6x^2-72=0
a = 6; b = 0; c = -72;
Δ = b2-4ac
Δ = 02-4·6·(-72)
Δ = 1728
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{1728}=\sqrt{576*3}=\sqrt{576}*\sqrt{3}=24\sqrt{3}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-24\sqrt{3}}{2*6}=\frac{0-24\sqrt{3}}{12} =-\frac{24\sqrt{3}}{12} =-2\sqrt{3} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+24\sqrt{3}}{2*6}=\frac{0+24\sqrt{3}}{12} =\frac{24\sqrt{3}}{12} =2\sqrt{3} $
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